How To Find The Area With The Circumference

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Units

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Answer:

circumference

C = 75.3982237 in

In Terms of Pi π

circumference

C = 24 π in

Solutions

\[ \textbf{diameter} \, d = 2r \]\[d = two \times 12 \]\[d = 24 \]

\[ \textbf{circumference} \, C = 2 \pi r \]\[C = 2 \times \pi \times 12 \]\[C = 24 \pi \]\[C = 75.3982237 \]

\[ \textbf{surface area} \, A = \pi r^ii \]\[A = \pi \times 12^2 \]\[A = 144 \pi \]\[A = 452.389342 \]

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Circle Shape

Circle Geometric Shape with Radius
r = radius
d = diameter
C = circumference
A = area
π = pi = 3.1415926535898
√ = square root

Calculator Employ

Utilise this circumvolve computer to detect the surface area, circumference, radius or diameter of a circumvolve. Given whatsoever ane variable A, C, r or d of a circumvolve you lot tin can calculate the other three unknowns.

Units: Note that units of length are shown for convenience. They do not affect the calculations. The units are in place to requite an indication of the order of the results such as ft, ft² or ftⁱⁱⁱ. Any other base of operations unit can be substituted.

Circle Formulas in terms of Pi π, radius r, and diameter d

Radius and Diameter:

r = d/2
d = 2r

Area of a circle:

A = πr² = πd²/4

Circumference of a circumvolve:

C = twoπr = πd

Circumvolve Calculations:

Using the formulas above and additional formulas y'all can summate properties of a given circle for any given variable.

Calculate A, C and d | Given r
Given the radius of a circle calculate the surface area, circumference and bore. Putting A, C and d in terms of r the equations are:

\[A = \pi r^2 \]

\[C = 2 \pi r \]

\[d = 2r \]

Calculate r, C and d | Given A
Given the area of a circle summate the radius, circumference and diameter. Putting r, C and d in terms of A the equations are:

\[r = \sqrt{\frac{A}{\pi}} \]

\[C = 2 \pi r = 2 \pi \sqrt{\frac{A}{\pi}} \]

\[ d = 2r = 2 \sqrt{\frac{A}{\pi}} \]

Calculate A, r and d | Given C
Given the circumference of a circle summate the radius, expanse and diameter. Putting A, r and d in terms of C the equations are:

\[r = \frac{C}{2 \pi} \]

\[A = \pi r^2 = \pi \left(\frac{C}{2 \pi}\right)^2 = \frac{\pi C^two}{four \pi^2} = \frac{C^two}{4 \pi} \]

\[d = 2r = \frac{2C}{2 \pi} = \frac{C}{\pi} \]

Summate A, C and r | Given d
Given the diameter of a circle summate the radius, area and circumference. Putting A, C and r in terms of d the equations are:

\[r = \frac{d}{2} \]

\[A = \pi r^2 = \pi \left(\frac{d}{2}\right)^ii = \frac{\pi d^two}{4} \]

\[C = 2 \pi r = 2 \pi \frac{d}{two} = \pi d \]

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